Math, asked by babitagautam134, 1 year ago

1/cot^A+1/1+tan^2A=1/1-sin^2A-1/cosec^A

Answers

Answered by vishalhirani09ow7o70
0

Answer:


1+cot^2 = cosec^2


1+tan^2 = sec^2


(1/cosec^2)/sec^2 = 1/-sin^2/cosec^2


L.H.S = 1/cosec^2 = sin^2


sin^2/sec^2


sin^2/1/cos^2


= sin^2cos^2


sin^2(1-sin^2)


sin^2 - sin^4



R.H.S =


1/ -sin^2 x sin^2/1


= -1


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