Math, asked by bariurvi, 6 months ago

( 1+ cot A - cosec A) ( 1+ tan A + sec A) =2​

Answers

Answered by raviparmar2002
2

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Step-by-step explanation:

by multiplying we get

1 + cotA - cosecA + tanA + cotAtanA - cosecAtanA + secA + cotAsecA - cosecAsecA

= 1 + cotA - cosecA + tanA + 1 - secA + secA + cosecA - cosecAsecA

= 2 + cotA + tanA - cosecAsecA

( cotA + tanA = cosA/sinA + sinA/cosA

= cos²A + sin²A / sinA•cosA

= 1/sinAcosA

= cosecAsecA)

= 2 + cosecAsecA - cosecAsecA

= 2

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