Math, asked by maria992, 8 months ago

(1+ cot A - cosec A ) ( 1+ tan A + secA ) =2

Answers

Answered by umarani94743
2

Step-by-step explanation:

(1+cot A - cosec A ) (1+ tan A + sec A ) = 2

[ 1+ 1/tan A - 1/ sin A ] [ 1+ sin A/ cos A + 1/cos A ] = 2

[ sin A - tan A +1 / tan A. sin A ] [ cos A + sin A +1 / cos A ]

[(cos A + sin A) + 1 ] [( cos A + sin A) -1] / tan A. cos A

( cos A + sin A )² - (1)² / tan A. cos A

cos²A+sin²A+2cos A. cos A-1 / tan A cos A

1+2cosA. sin A -1 / sin A. cos A

2cos A. sin A / cos A. sin A = 2

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