Question

(1+cot-cos)(1+tan+sec)=2​

Answer 1

$\huge\red{\boxed{\mathbb{\fcolorbox{orange}{violet}{\red{BRAINLIEST}}}}}$

L.H.S.

= ( 1 + cot - cos ) ( 1 + tan + sec )

= ( 1 + cos/sin - cos ) ( 1 + sin/cos + 1/cos)

= ( 1 + ( cos - sin.cos)/ sin ) ( 1+ (sin + 1)/cos )

= [ {sin + (cos-sin.cos) } / sin ] [ {cos + (sin+1)}/cos]

= TO.BE CONTINUED.

HOPE IT WILL HELP A LITTLE BIT.