Question

(1+cot-cosec)(1+tan+sec)=2

Answer 1

Answer:

=(1+cos/sin-1/sin) (1+sin/cos+1/cos)

=[(sin+cos-1) /sin][(cos+sin+1)/cos] =[(sin+cos) ^2-1]/sin.cos

=[sin^2+cos^2+2sin.cos-1]/sin.cos

=[1+2sin.cos-1]/sin.cos

=2sin.cos/sin.cos

=2

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