Question

(1+cot-cosec) (1+tan+sec) =2

Answer 1

Answer:

Hey buddy you have not mentioned the t ratios of standard angles so i cant help but you can ask me in comments ;)

Answer 2

Answer:

let the angle be A so,

(1+cotA-cosecA) (1+tanA+secA)

(1+(cosA/sinA)-(1/sinA)) (1+(sinA/cosA)+(1/cosA))

((sinA+cosA-1)/sinA) ((sinA+cosA+1)cosA

((sinA+cosA)^2 - 1^2)/sinA cosA

(sin^2 A + cos^2A + 2sinAcosA -1)/sinA cosA

(1+2sin A cos A - 1)/ sinA cosA

(2sinA cos A)/sinA cos A

2=2

L.H.S= R.H.S