Math, asked by gold7885361, 1 month ago

1+ cot square theta by 1+ tan square theta is equal to​

Answers

Answered by srameezj
0

Answer:

Answer

1+cot

2

θ

1+tan

2

θ

=

1+

tan

2

θ

1

1+tan

2

θ

(

1−cotθ

1−tanθ

)

2

=

(

tan

2

θ

tan

2

θ+1

)

1+tan

2

θ

=

1−

tanθ

1

1−tanθ

2

=tan

2

θ

(tanθ(

tanθ−1

1−tanθ

))

2

=(−tanθ)

2

=tan

2

θ.

Answered by MrDgp
0

Answer:

Answer</p><p></p><p></p><p></p><p>1+cot2θ1+tan2θ=1+tan2θ11+tan2θ</p><p></p><p>(1−cotθ1−tanθ)2=(tan2θtan2θ+1)1+tan2θ</p><p></p><p>=⎝⎜⎜⎛1−tanθ11−tanθ⎠⎟⎟⎞2=tan2θ</p><p></p><p>(tanθ(tanθ−11−tanθ))2</p><p></p><p>=(−tanθ)2</p><p></p><p>=tan2θ.</p><p></p><p>

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