Question

(1+cot+tan)(sin-cos)/sec^3-cosec^3=sin^2cos^2


answer it

Answer 1

Answer:

proved

Step-by-step explanation:

Given (1 + cotx + tan x)(sinx - cos x) / sec^3 x - cosec^3 x

 (1 + cosx/sinx + sinx/cosx)(sinx - cosx) / 1/cos^3 x - 1/ sin^3 x

(sin x cos x + sin^2 x + cos^2 x / sinx cos x)(sinx - cos x) / sin^3 x - cos^3x / sin^3xcos^3x

(sinxcosx + sin^2 x + cos^2 x)(sin x - cos  x)/sinxcosx x sin^3 xcos^3 x / sin^3 x - cos^3 x

  This is in the form of  a^3 - b^3 = (a - b)(a^2 + ab + b^2)

So we get

sin^3 x - cos^3 x / sinx cosx  x  sin^3 x cos^3 x / sin^3 x - cos^3 x

 sin^3 x cos^3 x/sin x cos x

 = sin^2 x cos^2 x (proved)

  L.H.S = R.H.S

Answer 2

Step-by-step explanation:

your answer attached in the photo