1+cot theta-cosec theta )(1+tan theta +sec theta)=2 prove this
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Step-by-step explanation:
(1+cotA-cosecA)(1+tanA+secA)
=(1+cosA/sinA-1/sinA)(1+sinA/cosA+1/cosA)
=(sinA+cosA-1/sinA)(cosA+sinA+1/cosA)
=(sinA+cosA)²-1/sinAcosA
=sin²A+cos²A+2sinAcosA-1/sinAcosA
=1+2sinAcosA-1/sinAcosA
=2sinAcosA/sinAcosA
=2
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