Question

1 + cot theta + tan theta whole whole sin theta minus cos theta whole equal to sec theta by cosec squared theta minus cosec theta by sec squared theta

Answer 1

Answer: Hope it helps u..

Hint: In trignometry we can also prove LHS and RHS seperately equal to something and then prove that LHS=RHS.

Answer 2

(1 + Cotx + Tanx)(Sinx - Cosx) = Secx/Cosec²x   - Cosecx/Sec²x

Step-by-step explanation:

(1 + Cotx + Tanx)(Sinx - Cosx) = Secx/Cosec²x   - Cosecx/Sec²x

LHS

= (1 + Cotx + Tanx)(Sinx - Cosx)

= (1 + Cosx/Sinx + Sinx/Cosx)(Sinx - Cosx)

= (SinxCosx + Cos²x + Sin²x)(Sinx - Cosx) /(Sinx.Cosx)

=(Sin³x - Cos³x) /(Sinx.Cosx)

= Sin³x/Sinx.Cosx  - Cos³x/Sinx.Cosx

= Sin²x/Cosx  - Cos²x/Sinx

= Secx/Cosec²x  - Cosecx/Sec²x

= RHS

QED

Proved

(1 + Cotx + Tanx)(Sinx - Cosx) = Secx/Cosec²x   - Cosecx/Sec²x

Learn more:

1/secx-tanx -1/cos = 1/cosx - 1/secx+tanx

https://brainly.in/question/8160834

cosX-4sinx=1 then sinx+4cosx[tex] cos(x) - Brainly.in

https://brainly.in/question/8892362