Question

(1+cot x - cosec x)(1+tan x + sec x)=2​

Answer 1

Answer:

Mark me as a Brainlist plz.

Step-by-step explanation:

ur answer is there in image

Answer 2

Answer:

2=RHS

Proved

Step-by-step explanation:

$(1 + cosx - cscx)(1 + tanx + secx) = 2$

$lhs = (1 + cotx - cscx)(1 + tanx + secx)$

$(1 + \frac{cosx}{ sinx} - \frac{1}{sinx} )(1 + \frac{sinx}{cosx} + \frac{1}{cosx} )$

$( \frac{sinx + cosx - 1}{sinx} )( \frac{cosx + sinx + 1}{cosx} )$

$\frac{ {(sinx + cosx)}^{2} - 1 }{sinx - cosx}$

$\frac{ {sin}^{2}x + {cos}^{2} x + 2sinxcosx - 1}{sinxcosx}$

$\frac{1 + 2sinxcosx - 1}{sinxcosx}$

$= 2$

$hence \: proved$