(1 + cot2Ɵ)(1 - cos2Ɵ) =
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Answer:
cos2Ɵ + cos2Ɵ x cot2Ɵ = cot2Ɵ
LHS=
taking cos2Ɵ common we get cos2Ɵ (1+ cot2Ɵ) = cos2Ɵ x cosec2Ɵ = cos2Ɵ x 1/ sin2Ɵ = cot2Ɵ = R.H.S
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