(1-cot200°)(1-cot25°)
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cot 200=cot ( 180+20)
cot 200=cot20 We have…
(1−cot 20)(1−cot 25) But tanx− sinx
cosx or 1
cos x
=
tan x sin x So we have
20
cos 25
1−
(1− cos
sin 20 )(
sin 25 )
cot 200=cot20 We have…
(1−cot 20)(1−cot 25) But tanx− sinx
cosx or 1
cos x
=
tan x sin x So we have
20
cos 25
1−
(1− cos
sin 20 )(
sin 25 )
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