Question

(1+cot²a)tana/seca = cota

Answer 1

(1+cot²a)tana/ =sec²a cota

Step-by-step explanation:

$L.H.S.\\\\=\frac{(1+Cot^{2}A)TanA }{Sec^{2} A} \\=\frac{(Cosec^{2}A)Tan A}{sec^{2} A} \\=\frac{[\frac{1}{Sin^{2}A}*\frac{SinA}{CosA}]}{sec^{2} A} \\=\frac{\frac{1}{CosA.SinA} }{Sec^{2} A} \\=\frac{Cos^{2}A }{CosA.SinA}} \\=\frac{CosA}{SinA} \\=CotA$