Math, asked by dharmitshah5604, 10 months ago

1/cotA+1/cosA=secA-tanA=1

Answers

Answered by asifhasan2708

1

Answer:

your question had a slight mistake.

Step-by-step explanation:

(1/cotA+1/cosA)(secA-tanA)

=(tanA+secA)(secA-tanA)

=sec^2A - tan^2A

=1

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