Math, asked by ankitsinghabd2006, 9 months ago

(1+cotA-cosecA)(1+tanA+secA)

Answers

Answered by sandy1816
1

Step-by-step explanation:

(1+cotA-cosecA)(1+tanA+secA)

=(1+cosA/sinA-1/sinA) (1+sinA/cosA+1/cosA)

=(sinA+cosA-1)/sinA (cosA+sinA+1)/cosA

=(sinA+cosA)²-1/sinAcosA

=2sinAcosA/sinAcosA

=2

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