Math, asked by Myfamily62341, 10 months ago

(1+cotA-cosecA) (1+tanA+secA)=2

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Answered by bedanta89

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Answered by sandy1816

$(1 + cota - coseca)(1 + tana + cota) \\ \\ = ( \frac{sina + cosa - 1}{sina} )( \frac{cosa + sina + 1}{cosa} ) \\ \\ = \frac{( {sina + cosa)}^{2} - 1 }{sinacosa} \\ \\ = \frac{2sinacosa}{sinacosa} \\ \\ = 2$

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(1+cotA-cosecA) (1+tanA+secA)=2​

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(1+cotA-cosecA) (1+tanA+secA)=2