Math, asked by shivkumarchauhan1490, 11 months ago

(1+cota-coseca) (1+tana+seca)=2

Answers

Answered by sandy1816

1

Step-by-step explanation:

(1+cotA-cosecA)(1+tanA+secA)

=(sinA+cosA-1/sinA)(cosA+sinA+1/cosA)

=(sinA+cosA)²-1²/sinAcosA

=sin²A+cos²A+2sinAcosA-1/sinAcosA

=2sinAcosA/sinAcosA

=2

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