Math, asked by karwajaiaditya, 1 year ago

(1+CotA-CosecA)(1+tanA+SecA)=2

Answers

Answered by sandy1816

0

Step-by-step explanation:

your answer attached in the photo

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Answered by Anonymous

0

Step-by-step explanation:

(1+CosA/SinA-1/SinA)(1+ SinA/CosA+1/CosA)

(SinA+CosA-1)/SinA * (CosA+SinA+1)/CosA

(SinA+CosA)² - (1)² / SinA*CosA

Sin²A+Cos²A + 2SinACosA - 1/SinA*CosA

1 + 2SinACosA - 1 / SinACosA

2SinA*CosA/SinA*CosA

= 2

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