Question

[1+cotA-cosecA] {1+tanA+secA} = 2

Answer 1

answer....................

Answer 2

$(1 + cota - coseca)(1 + tana + cota) \\ \\ = ( \frac{sina + cosa - 1}{sina} )( \frac{cosa + sina + 1}{cosa} ) \\ \\ = \frac{( {sina + cosa)}^{2} - 1 }{sinacosa} \\ \\ = \frac{2sinacosa}{sinacosa} \\ \\ = 2$