Question

(1+cotA-cosecA) (1+tanA+secA)=2​

Answer 1

Step by step explanation.

(1+ cosA/sinA - 1 / sinA) ( 1+ sinA/ cosA + 1 / cosA) = 2

={( sinA + cos A - 1) / sin A } { ( cos A + sin A + 1 ) / cos A }

= {( sin A + cos A)^2 - (1)^ 2} / sin A cos A

= (sinA^2 + cos A^2 + 2 sinA cos A - 1 ) / sin A cos A

= 1+2-1

= 2

hope it helps.....