Question

(1+CotA-CosecA) (1+tanA+SecA) = 2
Please explain step by step​

Answer 1

Answer:

2

Step-by-step explanation:

(1+cosA/sinA-1/sinA) (1+sinA/cosA+1/cosA)

After simplification

(sinAcosA+sin2A+sinA+cos2A+cosAsinA+cosA-cosA-sinA-1)/sinAcosA

2sinAcosA/sinAcosA

2