1+cotA / secA = sin²A/ 1-cosA proof it
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Answered by
3
Answer:
Step-by-step explanation:
1+cotA/secA
=1+(cosA/sinA)/(1/cosA)
=1+cos²A/sinA
=(sinA+cos²A)/sinA
sin²A/(1-cosA)
=(1-cos²A)/(1-cosA)
=(1+cosA)(1-cosA)/(1-cosA)
=1+cosA
∴, LHS≠RHS
But, if LHS
=1+cotA/cosecA
1+(cosA/sinA)/(1/sinA)
=1+cosA
Answered by
2
Hey mate here is your answer. I think it will help you. Therfore LHS is not equal to RHS.
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