Math, asked by priyanka9188, 11 months ago

1/cotA+tanA=secA+tanA

Answers

Answered by Anonymous

1

Answer:

1/CotA + tanA

= 1/cosA/sinA + sinA/cosA

= sinA cosA/Sin^2A + Cos^2A

= sinA cosA

RHS secA + tanA = 1+sinA/cosA

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