Math, asked by ramchetyadav999, 8 months ago

(1+cotA+tanA)(sinA-cosA)​

Answers

Answered by sandy1816
1

Step-by-step explanation:

(1+cotA+tanA)(sinA-cosA)

=(sinAcosA+cos²A+sin²A/sinAcosA)(sinA-cosA)

={(sinA-cosA)(sin²A+cos²A+sinAcosA)/sinAcosA}

=sin³A-cos³A/sinAcosA

=sin²A/cosA-cos²A/sina

=tanAsecA-cotAcosecA

Answered by rakeshlic1236
1

Answer:

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Step-by-step explanation:

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