(1+cotA+tanA) (sinA-cosA) =sec^3A-cosec^3A/sec^2A-cosec^2A
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Answer:
Hope that it will help you!!
Step-by-step explanation:
(1+cosA/sinA+sinA/cosA)(sinA-cosA) = (sinAcosA+sin^2A+cos^2A / sinAcosA)(sinA-cosA) = (sinAcosA+1 /sinAcosA )(sinA-cosA) =cosecAsecA(sinAcosA+1)(sinA-cosA) =cosecAsecA(sin^2acosA+sinA-sinAcos^2A-cosA) =cosecAsecA(cosA{sin^2A-1)-sinA{cos^2A-1}) =cosecAsecA(cos^3A-sin^3A) =cosecAsecA(1/sec^3A-1/cosec^3A)On multiplying by cosecAsecA =secA/cosec^2A-cosecA/sec^2a
which is equal to the proof!!!
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