Math, asked by Sachin800786, 10 months ago

(1+cotA+tanA) (sinA-cosA) =sec^3A-cosec^3A/sec^2A-cosec^2A

Answers

Answered by KCxSHIVAM
9

Answer:

Hope that it will help you!!

Step-by-step explanation:

(1+cosA/sinA+sinA/cosA)(sinA-cosA)                                         = (sinAcosA+sin^2A+cos^2A / sinAcosA)(sinA-cosA)                                         = (sinAcosA+1 /sinAcosA )(sinA-cosA)                                         =cosecAsecA(sinAcosA+1)(sinA-cosA)                                          =cosecAsecA(sin^2acosA+sinA-sinAcos^2A-cosA)                                         =cosecAsecA(cosA{sin^2A-1)-sinA{cos^2A-1})                                         =cosecAsecA(cos^3A-sin^3A)                                         =cosecAsecA(1/sec^3A-1/cosec^3A)On multiplying by cosecAsecA                                         =secA/cosec^2A-cosecA/sec^2a 

which is equal to the proof!!!

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