Math, asked by chaitanyasharma4558, 9 months ago

1+cota+tana)(sina-cosa)=seca/cosec^2a-cosec/sec^2a

Answers

Answered by jrjw512
1

Answer:

Step-by-step explanation:

=(1 + cosa/sina + sina/cosa)(sina-cosa)

= sina + cosa +sin^2 a /cosa -cosa -cos^2 a /sina - sina

= Sin^2 a /cosa - cos^2 a /sina

= Seca/cosec^2 a - coseca /sec^2 a

Hence ,proved

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