Question

(1+cotA+tanA)(sinA-cosA)=secA/cosec^2A-cosecA/sec^2A

Answer 1

+cotA+tanA)(sinA−cosA)(1+cot⁡A+tan⁡A)(sin⁡A−cos⁡A)

=(sinA−cosA)+cotA(sinA−cosA)+tanA(sinA−cosA)=(sin⁡A−cos⁡A)+cot⁡A(sin⁡A−cos⁡A)+tan⁡A(sin⁡A−cos⁡A)

=(sinA−cosA)+(cosA−cotAcosA)+(tanAsinA−sinA)=(sin⁡A−cos⁡A)+(cos⁡A−cot⁡Acos⁡A)+(tan⁡Asin⁡A−sin⁡A)

=tanAsinA−cotAcosA

Answer 2

Step-by-step explanation:

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