Question

(1+cotA+tanA)(sinA -cosA)÷sin³A-cosec³A = sin²Acos²A

Answer 1

Answer:

sec²A / [ 1 + cot²A ]

First express everything in terms of sine and cosine.

= 1 / cos²A [ 1 + cos²A / sin²A ]

I want to get rid of the sin²A in the denominator of the denominator. So I will multiply every term by sin^2(a). Note that the cos^2(a) does not get multiplied by sin^2(a), as it is not a separate term; the multiplication is happening in the brackets.

Answer 2

Answer:

sec²A / [ 1 + cot²A ]

First express everything in terms of sine and cosine.

= 1 / cos²A [ 1 + cos²A / sin²A ]

I want to get rid of the sin²A in the denominator of the denominator. So I will multiply every term by sin^2(a). Note that the cos^2(a) does not get multiplied by sin^2(a), as it is not a separate term; the multiplication is happening in the brackets.