Math, asked by yuvika5548, 7 months ago

(1+cotA+tanA)(sinA-cosA)=sinAtanA-cotAcosA

Answers

Answered by De20va07

1

Step-by-step explanation:

L.H.S = (1+cotA+tanA)(sinA-cosA)

= (sinA+sinAcotA +tanAsinA-cosA -cosAcotA -tanAcosA)

=(sinA+sinAcosA/sinA+tanAsinA-cosA-cosAcotA -cosAsinA/cosA)

= (sinA+cosA+tanAsinA -cosA- cosAcotA -sinA)

= tanAsinA -cosAcotA

= sinAtanA-cotAcosA

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