( 1 + cotAsquare) tanA / secAsquare
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Solution :
[( 1+cot²A)tanA]/(sec²A)
= ( cosec² A tanA)/sec²A
_____________________
Since ,1+cot²A = cosec² A
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= [(1/sin²A)tanA]/(1/cos²A)
= (tanA)/(sin²A/cos²A)
= (tanA)/tan²A
= 1/tanA
= cotA
••••••
[( 1+cot²A)tanA]/(sec²A)
= ( cosec² A tanA)/sec²A
_____________________
Since ,1+cot²A = cosec² A
_____________________
= [(1/sin²A)tanA]/(1/cos²A)
= (tanA)/(sin²A/cos²A)
= (tanA)/tan²A
= 1/tanA
= cotA
••••••
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