Question

1-cotsquare45/1+sinsquare90

Answer 1

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Answer 2

Solution: cot45°= 1 and sin 90°= 1 then (1-cot^2 45° )/1+sin^2 90°

=( 1-cos^2 45/sin^2 45) / 1+sin^2 90

[ Take LCM in numerator]

Now =( sin^2 45 - cos^2 45)/ sin^2 45( 1+sin^2 90) = 0 [ since cos 45= sin45 ] then numerator becomes zero .so yr answer is zero....