(1+ cotx - cosecx), (1 + tanx + secx) = 2 prove LHS=RHS
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Hope my answer helps you mate :-)
Step-by-step explanation:
cotX = =CosX/SinX
CosecX= 1/sinX
tanX=sinX/cosX
secX=1/c
sinx +cosx/sinx-
1/sinX)(1+sinX/CosX + 1/cosX)
(sinX + cosX-1/sinx)(cosx+sinX+1/CosX)
Let Sinx+Cosx Be A and 1 be B
By identity a²-b²
[(sinx+cosx)² - 1]/sinxcosx
sin²x + cos²x +2sinxcosx -1/sinxcosx
Now as sin²x + cos²x = 1
2sinxcosx/sinxcosx
2
LHS=RHS
Hence proved
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