1 cow costs 1 rupee. 1 buffalo costs 5 rupees. 20 goats cost 1 rupee. With 100 rupees, i bought a total of 100 animals of all three types. How many of each animal did i buy?
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Answered by
3
Hello mate,
Interesting question!
x + y + z = 100
0.05x + y +5z = 100. …. x is no . of goats ..0.05 rupees can buy 1 goat.
If u solve the above you get (99/19)z = 100 - y
If u take y as 1 then the numerator gets cancelled on both sides.
Hence you get
X = 80
Y = 1
Z = 19 .
hope this helps you out!
Interesting question!
x + y + z = 100
0.05x + y +5z = 100. …. x is no . of goats ..0.05 rupees can buy 1 goat.
If u solve the above you get (99/19)z = 100 - y
If u take y as 1 then the numerator gets cancelled on both sides.
Hence you get
X = 80
Y = 1
Z = 19 .
hope this helps you out!
Answered by
4
Answer:
Hello mate,
Interesting question!
x + y + z = 100
0.05x + y +5z = 100. …. x is no . of goats ..0.05 rupees can buy 1 goat.
If u solve the above you get (99/19)z = 100 - y
If u take y as 1 then the numerator gets cancelled on both sides.
Hence you get
X = 80
Y = 1
Z = 19 .
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