Question

1 Cube + 2 cube + 3 Cube power 1 by 2​

Answer 1

1 Cube = 1

2 Cube = 8

3 Cube = 27

So,

1 Cube + 2 Cube + 3 Cube power 1 by 2

= (1+8+27)^1 / 2

= (36)^1 /2

= 36/2

= 18

Answer 2

$\pink{hii \: mate \: if \: you \: here \: is \: your \: reqired \: answer }$

Given:-

$({1}^{3} + {2}^{3} + {3}^{3} ) ^{ \frac{1}{2} }$

Solution:-

$\green{ {1}^{3} = 1}$

$\green{ {2}^{3} = 8}$

$\green{ {3}^{3} = 27}$

${(1 + 8 + 27 )}^{ \frac{1}{2} }$

${36}^{ \frac{1}{2} }$

$\blue{ { {6}^{2} }^{ \frac{1}{2} }}$

2×1/2=1

6 power 1

answer is 6