1 cubic centimetre of 0.1 normal hcl is added to 1 litre solution of sodium chloride the ph of the resulting solution will be
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Data:
Volume of HCL = 1 cm³ = 1/1000 = 0.001 L
Volume of NaCl = 99 cm³ = 99/1000 = 0.099 L
Normality of HCL = 0.1 N
pH of the resulting solution = ?
Solution:
Normality volume = (0.1) (0.001)
Normality volume = 0.0001 L
Volume of solution = Volume of NaCl + Volume of HCL
Volume of solution = 0.099 + 0.001
Volume of solution = 0.1 L
Since NaCl is a salt and is neutral so it does not effect pH of a solution.
Now,
Normality of HCL in a resulting solution = 0.0001 / 0.1
Normality of HCL in a resulting solution = 0.001 N
So,
pH = - log [H⁺]
pH = - log (0.001)
pH = 3
which shows that the pH of the resulting solution is 3
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