Math, asked by vishalk73692, 2 months ago

1. d/DX (sec x . cosec x )
2. d/DX ( tan x . sec x )
3. d/DX (cosec x . cot x ) ​

Answers

Answered by Anonymous
11

Y =(Sec x . Cosec x)

 \frac{dy}{dx}  =  sec x. ( - cotx)  + cosecx.tanx

 \frac{dy}{dx}  =  - cotx.secx + cosecx.tanx

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Y = (Tanxx . Secx)

 \frac{dy}{dx}  = Sec x

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Y = Cosecx. Cotx

 \frac{dy}{dx}  =  - cosecx

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