Math, asked by swarajkharse2808, 3 months ago

1/D-m f(x), where D =d/dx
and m is constant, is equal to

Answers

Answered by prajyotyadav39
0

Answer:

1/D-m f(x), where D =d/dx

and m is constant, is equal to

Answered by ravilaccs
0

Answer:

$$\begin{aligned}&\frac{1}{D-m} f(x) \\&=e^{m x} \int f(x) e^{-m x} d x\end{aligned}$$

Step-by-step explanation:

$\frac{1}{D-m} f(x) where $D \equiv \frac{d}{d x}$

Where $m$ is constant

$D$ is a differential operator

$$D \equiv \frac{d}{d x}$$

Now simplify the expression

\frac{1}{D-m} f(x)$ where $D \equiv \frac{d}{d x}$

$$\begin{aligned}&\frac{1}{D-m} f(x) \\&=e^{m x} \int f(x) e^{-m x} d x\end{aligned}$$

The above concept is used in finding a particular integral of a differential equation

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