Question

1. De Morgan's Law for propositional calculus states (where t(A) is the interpretation of A)
a. ¬(p ⇒ q) ⇒ p ¬q ∧
b. p ⇒ (p ⇒ p)
c. t(q ¬q) = 0 ∧
nothing​

Answer 1

Answer:

b

Explanation:

b is correct answer.

easy question