Question

1. DEF is an isosceles triangle with DE=DF. S and T are points on DE and DF respectively such that DS=DT. Prove that FS = ET.


please put the figure formed and do mention the steps​

Answer 1

Step-by-step explanation:

In △DEF

∠EDF+∠DEF+∠DFE=180

o

⇒ ∠DEF+∠DFE=180

o

−∠EDF

⇒ ∠DEF+∠DFE=180

o

−40

o

=140

o

i)

In △BCF, CB=CF

⇒ ∠CFB=∠CBF (Isos.△CBF)

or ∠EFD=∠CBF.(ii)

In △AEC,CA=CE⇒∠CEA=∠CAE (Isos. △ prop.)iii)