1) Derive the equation of a plane in a normal form (5 marks)
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Let L be the line whose perpendicular distance from origin is P, angle XOA =ѳ
Draw AM perpendicular to x-axis.
Then AM=Psinѳ, OM=Pcosѳ
Point A=(Pcosѳ Psinѳ)
Now slope of OA =tanѳ
OA is perpendicular to Line L.
Equation of line is
✈ y-y1=m(x-x1) [Point slope form]
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