Question

1. Describe the motion of the object.

2. What is the maximum height reached by the object?

3. What is the minimum height reached by the object?

4. What is the amplitude of the graph?

5. How long will it take the object to complete one cycle?

6. What equation represents the graph?​

Answer 1

Answer:

2. 7cm

3. 1cm

Step-by-step explanation:

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Answer 2

$\huge\star\underline {\mathtt \orange{❥A} \mathfrak\blue{n}\mathfrak\blue{s} \mathbb\purple{ w}\mathtt\orange{e} \mathbb\pink{r}}\star\:$

1 . You can describe the motion of an object by its position, speed, direction, and acceleration. An object is moving if its position relative to a fixed point is changing. Even things that appear to be at rest move.

2. The maximum height of the object is the highest vertical position along its trajectory. The maximum height of the projectile depends on the initial velocity v0, the launch angle θ, and the acceleration due to gravity. The unit of maximum height is meters (m).

3.Initial velocity of the object is u.

Acceleration due to gravity acting on the object is a=−g

At maximum height (h) attained, velocity of the object is zero i.e. v=0

Using v² −u 2=2ahOr 0−u²2l

=2(−g)h

⟹ h=

2g

u

2

Thus we get h∝u

4.Amplitude is the distance between the center line of the function and the top or bottom of the function, and the period is the distance between two peaks of the graph, or the distance it takes for the entire graph to repeat. ... This is shown in the graph as the amplitude is 1 and the period is 2π.

5. The period of the object's motion is defined as the time for the object to complete one full cycle. Being a time, the period is measured in units such as seconds, milliseconds, days or even years.

6. For graph (ii), two points are given,

A(1,1) and B(−1,−1)x 1

=1x

2

=−1

y

1

=1

y

2

=−1

Equation of line when two points are given-

(y−y 1 )=(x 2

−x 1 )(y 2 −y1

)

(x−x

1

)

⇒(y−1)=

−1−1

−1−1

(x−1)

⇒(y−1)=

−2

−2

(x−1)

⇒(y−1)=(x−1)

⇒y=x

Hence graph (ii) represents (y=x) equation.