Question

1. Determine the minimum frequency required to have Photoelectric effect for an EM radiation, when incident on a zinc metal surface.

Answer 1

Answer:

sorry but i am in 10 standard its out of my  reach

Answer 2

Answer:

Explanation:

work function of zinc = 4.33 eV

energy of em wave (in joules ) = h$v$

1 eV = 1.6 × 10¹⁹

4.33 eV = 4.33×1.6×10⁻¹⁹ J

4.33×1.6×10⁻¹⁹ = 6.623 × 10⁻³⁴ ×$v$

$v$ = 4.33×1.6×10⁻¹⁹÷  6.623 × 10⁻³⁴ = 1.04×10¹⁴ Hz