Question

(1) Determine the nature of the roots for the quadratic equation
√3x² + 2√2x – 2/3=0​

Answer 1

Step-by-step explanation:

to determime the nature of roots:

D=b²+4ac

=(2√2)² + 4 x √3 x -2/3

8+8√3/3>0

the roots will be two different roots

Answer 2

Answer:

Nature of root=

 $=b^{2} +4ac\\=8-4*\sqrt{3} *\frac{2}{3} \\=8-\frac{8}{\sqrt{3} } \\=8-4.618\\\\=3.382$

As it is greater than 0, the roots are unequal and rational