Question

(1) Determine the nature of the roots for the quadratic equation √3x*+√2x-2√3= 0
explain​

Answer 1

For this we first need to compare this equation with ideal equation i.e. ax^2+bx+c=0

Hence on comparing a=√3

b= √2 and c= (-2√3)

Step-by-step explanation:

If b^2-4ac>=0

then nature of roots is real otherwise unreal or imaginary.

b^2-4ac=(√2)^2-4*√3*(-2√3)

= 2+8*3

=2+24

=26 which is greater than zero

Hence nature of roots is real