(1) Determine the nature of the roots for the quadratic equation
√3x² + √2x - 2/3=0.
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Answer:
given equation, ✓3x² + 2✓2x - 2/3 = 0
here a equal to ✓3
b equal to 2✓2
and c equal to 2/3
discriminant , b² - 4ac= (2✓2)² - 4 * ✓3* 2/3
= 8 - 8/✓3
= 8✓3 - 8✓3/✓3
= 0/3
= 0
hence the roots are equal
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