1) Determine the value of d such that 15=3(mod d)
2) solve 8x=1(mod 11)
4
3) compute x, such that 10 =x (mod15)
4)solve 3x-2=0 (mod 11)
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I need help finding a solution of 9x≡24(mod21).
Here is what I tried, but it's wrong.
mod x is the positive value of x. mod 21=21.
9x≡24(mod21).
9x=24∗21
x=24∗21/9=56
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