Question

1
ליועג
Determine (x+1 ) is a factor of x³+x²+x+1​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$p(x) = {x}^{3} + {x}^{2} + x + 1$

$g(x) = x + 1$

$g(x) = 0$

$x + 1 = 0$

$x = - 1$

Now,

$p( - 1) = {( - 1)}^{3} + { (- 1)}^{2} + ( - 1) + 1$

$p( - 1) = - 1 + 1 - 1 + 1$

$p( - 1) = 0$

Yes, x+1 is a factor of x³+x²+x+1