1. Diagonal UK and HS of a Rhombus HUSK are of the length 10cm and 24cm. Find its side.
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1
Answer:
Let ABCD be the rhombus where UK = 10 cm and HS = 24 cm.
Let UK and HS intersect each other at O.
Now, diagonals of rhombus bisect each other at right angles.
Thus, we have
So, OK = 1/2 of UK
= (1/2×10) cm
= 5 cm
So, OS = 1/2 of HS
= (1/2×24) cm
= 12 cm
Triangle OKS is a right angled triangle (Property of rhombus)
By Pythagorean Theorem
OS² + OK² = KS²
(12 cm)² + (5 cm)² = KS²
144 cm² + 25 cm² = KS²
169 cm² = KS²
KS^2 = 169 cm²
KS = 13 cm
Thus, length of each side of rhombus is 13 cm.
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Answer:
13 CM
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