1.Differentiate between speed and velocity.
2.(a) Derive the equation of motion v = u +at, using graphical method.
(b) A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming the acceleration is uniform, find
(i) The acceleration.
(ii) The distance travelled by the train for attaining this velocity.
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Answer:
speed is a scalar quantity but velocity is a vector quantity
2)b)u=0,v=72km/h-20m/s ,t=5min=300sec
a=20-0/300
1/15m/s^2
s=ut+1/2at^2
s=0×300+1/2×1/15×300×300
s=3000m=3km
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